[Codewars] Kebabize

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▶  문제 : 

▶  내 답안 : 

import re
def kebabize(string):
    string = re.sub('[0-9]','',string)
    a = set([0]+[i for i in range(len(string)) if string[i] != string.lower()[i]]+[len(string)])
    b = sorted(list(a))
    c = []
    for i in range(len(b)) :
        try :
            c.append(string[b[i]:b[i+1]].lower())
        except :
            pass
    return '-'.join(c)

import re
def kebabize(string):
    string = re.sub('[0-9]','',string)
    if string == '' :
        return ''
    p = re.compile("[A-Z]")
    result = p.sub(lambda m : '-'+ m.group(0).lower(), string)
    if result[0] == '-' :
        return result[1:]
    else :
        return result

▶  모범답안 : 

def kebabize(s):
    return ''.join(c if c.islower() else '-' + c.lower() for c in s if c.isalpha()).strip('-')

import re

def kebabize(s):
    return re.sub('\B([A-Z])', r'-\1', re.sub('\d', '', s)).lower()

 

 

▶  배워야할 부분 : 정규표현식(r'\1'), islower(), isalpha()

import re

string = 'HiMyNameIsDebriswisdom'

1. r'\1' : itself(자기자신)

re.sub('([A-Z])',r'\1',string)
>>> 'HiMyNameIsDebriswisdom'

2. \B (빈칸아님), \b (빈칸)  

re.sub('\B([A-Z])',r'-\1',string)
>>> 'Hi-My-Name-Is-Debriswisdom'

string = 'Hi My Name Is Debriswisdom'
re.sub(r'\b([A-Z])',r'-\1',string) # r에 주목 : \b는 r'\b'로 작성해야함
>>> '-Hi -My -Name -Is -Debriswisdom'


3. strip() 사용

re.sub('([A-Z])',r' \1',string).strip()
>>>'Hi My Name Is Debriswisdom'

re.sub('([A-Z])',r'-\1',string).strip('-')
>>>'Hi-My-Name-Is-Debriswisdom'

 

- 정규표현식 관련

위키독스

 

- Case : Camel , Kebab, Snake, Pascal 

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